Constructing perpendiculars
Topics in this lesson
- Constructing the perpendicular bisector of a segment
- Constructing the midpoint of a segment
- Constructing a perpendicular to a line through a given point
- Copying a length
- Constructing a regular tessellation of the plane by squares
The perpendicular bisector of a line segment
Definition: The perpendicular bisector of a segment is
the line that is perpendicular (at a right angle) to the segment and goes
through the midpoint of the segment.
Theorem: The perpendicular bisector of a segment is the set of
all points that are the same distance from both the endpoints of the segment.
Note: A theorem is a mathematical fact that has been proved from more
basic facts. More about this later.
Constructing the perpendicular bisector of a segment
| Draw a circle whose center is one of the endpoints of the segment,
and whose raduis is more than half the length of the segment. |
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| Draw another circle with the same radius, whose center is the other endpoint
of the segment. |
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| Draw the line through the two points where the circles intersect. |
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Note: You don't have to draw the entire circle, but just the
arcs where the two circles intersect.
Spinoff: Construct the midpoint of a segment.
Construct the perpendicular bisector. The midpoint of the segment
is where the perpendicular intersects the line (by definition).
Axiom: Given a line and a point, there is one and only one perpendicular
to the line through the point.
Note: An axiom is the most basic type of mathematical fact. Axioms
are the starting rules which are just assumed, not proved. (You have
to start somewhere.) The first theorems are proved from definitions
and axioms.
Spinoff: Construct the perpendicular to a line through a given point.
The main idea is to construct an appropriate line segment on the line, then construct
the perpendicular bisector of this segment.
Construction steps
| A. If the point is not on the line, |
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| draw a circle whose center is the given point, and whose radius is
large enough so that the circle and line intersect in two points, P and
Q. |
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| B. If the point is on the line, |
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| draw a circle whose center is the given point; the circle and line
intersect in two points, P and Q. |
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| Construct the perpendicular bisector of segment PQ. |
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Copy a length
You are given a line segment, and would like to construct another segment
of the same length at a given point on another line.
Construction steps
| You are given a line segment AB with length L, and would like to construct
another segment of the same length at a given point C on another line. |
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| Use the endpoints A and B to set your compass opening. Draw a circle
with that raduis and center C. Pick one of the intersection points of the
line and the circle as one endpoint; C is the other endpoint. |
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Note: You don't have to draw the entire circle, but just the
arc where the line and circle intersect.
Construct a tessellation of the plane
by squares
Make some square graph paper (a tessellation of the plane
by squares) using only straightdge and compass. Follow these steps:
- Draw a line.
- Set your compass opening to the length you want for the side of a square.(Use at least 1 inch, or it will be too small to draw accurately.)
- Draw a circle with that radius and center on the line.
- Draw more circles with the same radius whose centers are the
points where the last circle intersected the line.
- Continue drawing circles along the line.
- For each circle center, draw a perpendicular to the original line
through that point.
- Mark off the same length (radius) on each of the perpendicular lines,
starting from the circle centers.
- Draw lines parallel to the original lines using the marks you just made.
Group problems
- Consider the equilateral triangle tessellation constructed in the first class.
You may use the points of intersection of all the circles, and any
lines through those points. Is it possible to construct a
right angle
with these points and lines? Why or why not?
Is it possible to construct a
square
with these points and lines? Why or why not?
Homework problem
-
Invent a method to construct a single square with
straightedge and compass, using as few steps as possible.
Do the construction
and write clear instructions.
Definition: A median of a triangle is a line segment
that goes from a vertex to the midpoint of the opposite side.
- Construct two random triangles (one with an obtuse angle).
Make them big: one per page isn't too big. For each triangle,
- Construct the perpendicular bisectors of all three sides.
- Construct all three medians of the triangles (on the same drawing; use
a different color.)
- Make a conjecture about the perpendicular bisectors of the sides of any triangle.
- Make a conjecture about the medians of any triangle. (Hint: How could
three line segments intersect?)
Extensions (group or individual)
- Prove that the first construction in this lesson really does construct the
perpendicular bisector.
Use any definitions and theorems given so far. Remember that two points determine a line.
- How do you know that the perpendicular bisector goes through
the original point C, and is perpendicular to the original line?
- How do you know that that the new segment in the copy length
construction has the same length
as the old segment?
- Choose one square in the graph paper you
constructed and prove that all four of its sides have equal length.